Equation of continuity

1. Dec 8, 2016

joseph_kijewski

1. The problem statement, all variables and given/known data

You are watering your lawn with a hose when you put your finger over the hose opening to increase the distance the water reaches. If you are pointing the hose at the same angle, and the distance the water reaches increases by a factor of 4, what fraction of the hose opening did you block?

2. Relevant equations

3. The attempt at a solution

This seems very obvious to me. The density of the water would remain consistent, thus the equation would become A1v1=A2v2. Since t is consistent as long as the height the water is fired from is, I figured this means v2 must be 4 times v1. But the answer is 2 times? I've looked over this problem many times and I just can't see what I'm missing, it seems so obvious?

2. Dec 8, 2016

TSny

What do you mean by "t is consistent"? You'll need to review projectile motion to see how the range of a projectile depends on initial speed.

3. Dec 8, 2016

joseph_kijewski

Shouldn't x component be v*t, thus directly proportional to velocity?? By t is consistent, I mean that t must be consistent in both as h is consistent: -4.9t^2=h

4. Dec 8, 2016

TSny

When a football is kicked into the air, does the time of flight change if the initial speed is changed?

4.9t2 = h is for horizontal projection from a height h.

The statement of the problem is not clear about whether or not to take into account the initial height of the hose. I suspect that you are meant to neglect the initial height and imagine that the water essentially leaves the hose at ground level.

5. Dec 8, 2016

TSny

When you write the equation x = vt, what does v represent? Is it the initial speed, or is it the x-component of the initial velocity, or is it the y-component of the initial velocity, or something else?

6. Dec 8, 2016

joseph_kijewski

I guess I'm imagining the hose as horizontal, in which case I believe I would be right, but the angle isn't specified, so isn't it impossible to determine the answer?

7. Dec 8, 2016

TSny

Yes, if you interpret the problem as aiming the hose horizontally from some height h, then to quadruple the range you would need to quadruple the initial speed. As you noted, this is not the answer they wanted.

The problem statement mentions "pointing the hose at the same angle". This suggests that the hose is not horizontal, but tilted upward. However, the problem is still not clear regarding the initial height. See if you get the "right" answer if you assume the initial height is small enough to neglect. So, the water essentially leaves the hose at ground level at some unknown angle θo.

8. Dec 8, 2016

joseph_kijewski

Figured it out, thanks!

9. Dec 8, 2016

TSny

OK. Good work!