# Equation of e^z=w form

1. May 13, 2016

### Dousin12

1. The problem statement, all variables and given/known data
$$2e^z=\sqrt{2}+i\sqrt{2}\\e^z=\frac{\sqrt{2}+i\sqrt{2}}{2}$$
Then i write the right side as polar form and the abs(right hand side)=2 , and then multiplied with an angle. But in the answer there is only pi/4*i. which is the angle i get, but since the abs(right hand side)=2, why isn't there a "ln 2" in the solution?

Last edited by a moderator: May 13, 2016
2. May 13, 2016

### Ray Vickson

Please write your TeX/LaTeX properly; I have fixed up the above and have obtained
$$2e^z=\sqrt{2}+i\sqrt{2}\\e^z=\frac{\sqrt{2}+i\sqrt{2}}{2}$$
Anyway, the absolute value of the rhs is not 2.

Mod note: I fixed the contents of the original post.

Last edited by a moderator: May 13, 2016
3. May 14, 2016

### Dousin12

Yeah i saw when i went to bed, :D My bad. I wrote wrong on the calculator

Btw how do i write latex properly? I can't figure out how to do it!

4. May 14, 2016

### haruspex

If you right click on the equations Ray posted you should see an option to display the latex.

5. May 14, 2016

### Dousin12

2e^z=\sqrt{2}+i\sqrt{2}\\e^z=\frac{\sqrt{2}+i\sqrt{2}}{2}

this is what i see,

HOw to i get it to be latex? I thought just write $$on both sides? 6. May 14, 2016 ### SammyS Staff Emeritus You need$$ to terminate it.
$$2e^z=\sqrt{2}+i\sqrt{2}\\e^z=\frac{\sqrt{2}+i\sqrt{2}}{2}$$

7. May 14, 2016

### Ray Vickson

In your original submission (still echoed in the panel above my response) you will see that you used "[ tex ] some math [ /tex ]". The spaces you inserted inside [...] were a mistake: you should have "[t..x] some math [/t..x]" , where '..' means 'e'. The rest of your expression was perfectly OK.

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