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foo9008
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Homework Statement
the equation of flow aret given is [(pi)((r_o)^4 ) / 8μ ] [-d/ds (ρ +yz ) ] , but the ans that i got is - [(pi)((r_o)^4 ) / 8μ ] [-d/ds (ρ +yz ) ] , what's wrong with my working ?
thanks , i got the ans alreadyBvU said:Try the simpler $$\int_0^{r_0} (r_0^2 -r^2)\, r dr $$to avoid things like the ##r_0^3## (?) in your first step
The equation of flow rate is the volume of fluid that passes through a given area per unit time. It is typically represented as Q = AV, where Q is the flow rate, A is the cross-sectional area of the pipe or channel, and V is the velocity of the fluid.
Flow rate can be measured using a variety of methods, such as flow meters, pitot tubes, and orifice plates. These devices measure the velocity of the fluid and use it to calculate the flow rate using the equation Q = AV.
The flow rate of a fluid can be affected by several factors, including the viscosity of the fluid, the cross-sectional area of the pipe or channel, the velocity of the fluid, and the presence of any obstacles or restrictions in the flow path.
Flow rate can be expressed in a variety of units, depending on the application and the specific equation used. Some common units include cubic meters per second (m3/s), liters per minute (L/min), and gallons per minute (gpm).
The equation of flow rate is used in many real-life applications, such as in plumbing, hydraulics, and HVAC systems. It is also used in the design and operation of water treatment plants, irrigation systems, and water distribution networks.