a car starts from rest and acclerates down a straight track of length L= 1600m with a constant accleration. If the time it takes for the car to travel the final d= 100 m of the track (from 1500m to 1600m) is T=0.125s, then the acceleration of the car is.... the answer is 80.7 m/s^2(adsbygoogle = window.adsbygoogle || []).push({});

this isnt hw, it's actually practice for the final i have tommorow. I havent done this question in awhile, so im not sure how to do it. but here's what i think i should do... im having trouble finding which equation to use. well i have the initial x and final x, and t. and i need to find acceleration. so i think i need to use this formula:

[tex]X = x_0 + v_0*t + 1/2at^2[/tex]

100 = 1500 + 1/2at^2

x final should be 100 right? because the final 100 it needs to travel

and solve for a? doesnt really make sense. can someone offer some help on which equation i should use?

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# Homework Help: Equation of motion

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