- #1
emma3001
- 42
- 0
I have to find the equation of the plane that contains the line of intersection of x - y + 2y + 5 and 2x + 3y - z - 1 and is parallel to the line segment with normal vector [1, 2, -1].
I thought that I could go find the dot product of the normal vector I have [1, 2, -1] and the A B and C values for one of the two above equations.
x - y + 2y + 5 + k(2x + 3y - z - 1)=0
I rearrange it to get x(1 + 2k) + y(-1 + 3k) + z(2-k) + (5- k)=0. Now how can I find the value of k?
I thought that I could go find the dot product of the normal vector I have [1, 2, -1] and the A B and C values for one of the two above equations.
x - y + 2y + 5 + k(2x + 3y - z - 1)=0
I rearrange it to get x(1 + 2k) + y(-1 + 3k) + z(2-k) + (5- k)=0. Now how can I find the value of k?