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## Homework Statement

find the equation of the straight line which is perpendicular to the line 5x-3y-6=0 and passes through the point (-3,4)

## Homework Equations

## The Attempt at a Solution

-3y=-5x+6

where do i go from there

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- Thread starter nae99
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- #1

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find the equation of the straight line which is perpendicular to the line 5x-3y-6=0 and passes through the point (-3,4)

-3y=-5x+6

where do i go from there

Last edited:

- #2

dynamicsolo

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- #3

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itsequation from the point-slope form for a line.

-3y=-5x+6

-3(4)=-5(-3) + 6

-12=15+6

-12=21

should it be done like that

- #4

dynamicsolo

Homework Helper

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What is the slope-intercept form for -3y = -5x + 6 ? (What do you still need to do?)

Once you've done that, what does the equation tell you about the slope of this line you were given?

- #5

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What is the slope-intercept form for -3y = -5x + 6 ? (What do you still need to do?)

Once you've done that, what does the equation tell you about the slope of this line you were given?

honestly i have no idea what is slope intercept

- #6

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honestly i have no idea what is slope intercept

Then this problem is probably too advanced for you.

- #7

DaveC426913

Gold Member

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honestly i have no idea what is slope intercept

1] Reformulate the equation in the form of y=mx+b.

2] Do you know how to calculate the slope of a line? Rise over run?

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- #8

HallsofIvy

Science Advisor

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Do you know what is meant by thehonestly i have no idea what is slope intercept

- #9

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i suggest use y=mx+c....frst find the slope of the equation..n use y1-y2/x2-x2=....

- #10

Mark44

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Your expression needs parentheses. If a line contains the points (xi suggest use y=mx+c....frst find the slope of the equation..n use y1-y2/x2-x2=....

The expression you wrote would be interpreted to mean

[tex]y_1 - \frac{y_2}{x_2} - x_1[/tex]

but that's not what you meant.

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