find the equation of the straight line which is perpendicular to the line 5x-3y-6=0 and passes through the point (-3,4)
The Attempt at a Solution
where do i go from there
Finish putting the equation for the line into slope-intercept form, so that you can read what the slope is. What is the relationship between the slopes of two perpendicular lines? You can use that to find the slope of the line you are seeking. You are given a point which this new line must pass through, so you can get its equation from the point-slope form for a line.
If you're getting -12 = 21 , then that probably isn't what you need to do... You don't want to put ( -3, -4 ) into the original line's equation, because that point is not on the line you were given.
What is the slope-intercept form for -3y = -5x + 6 ? (What do you still need to do?)
Once you've done that, what does the equation tell you about the slope of this line you were given?
Do you know what is meant by the slope of a line? If not, then, as phinds says, you shouldn't be attempting a problem like this. If it hs been given as coursework, then you should consult your text book for the definition of "slope" and how the slopes of perpendicular lines are related.honestly i have no idea what is slope intercept
Your expression needs parentheses. If a line contains the points (x1, y1) and (x2, y2), then the slope m is given by m = (y2 - y1)/(x2 - xSUB]1[/SUB])i suggest use y=mx+c....frst find the slope of the equation..n use y1-y2/x2-x2=....