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Equation of the plane S

  1. Apr 27, 2009 #1
    1. The problem statement, all variables and given/known data

    S is the square of side 2 with one vertex at the origin, one edge along the positive y-axis, one edge in the xz-plane with x ≥ 0, z ≥ 0, and the normal is n = i - k .

    2. Relevant equations



    3. The attempt at a solution

    Can someone help me how to find the equation of this plane?
     
  2. jcsd
  3. Apr 27, 2009 #2

    HallsofIvy

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    One vertex is the origin, (0, 0, 0), and you know the normal vector. What more do you need? The plane containing the point (x0, y0, z0), with normal vector <A, B, C>, has equation A(x- x0)+ B(y- y0)+ C(z- z0)= 0.
     
  4. Apr 27, 2009 #3
    yes.. I tried (0,0,0) and I got x - z = 0 ? is this true?
     
  5. Apr 27, 2009 #4

    HallsofIvy

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    Strictly speaking, a "square" is not a plane, it lies in a plane, so this is a strangely worded question!

    Certainly, the origin, the corner (0,0,0) satisfies x- z= 0, the edge along the positive y- axis, (0, y, 0) satisfies x- z= 0, and the edge in the xz-plane, satisfying x- z= 0, (x, 0, x) is at right angles to (0, y, 0) (because <0, y, 0>.<x, 0, x>= 0). What more do you want?
     
    Last edited: Apr 27, 2009
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