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So if I have a kangaroo on planet Y with a specified gravity of 12m/s^2. If he jumps with an inital velocity of 8m/s, how far would he travel?
Equation that is y=(Vi^2)/2g
- Thread starter jacksonbobby5
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- #2
Hootenanny
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What have you attempted thus far? What are your thoughts?
- #3
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Well I thought I would use the formula y=Vi(time)+1/2g(time)^2, but I don't have a time, just initial velocity and gravity.
- #4
Hootenanny
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Which other kinematic equations do you know? You need to pick one with all the variables in that you know plus the one which you want to find out.
- #5
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Well, I also had read about an equation that is y=(Vi^2)/2g but I wasnt sure wether this was a valid equation or a kinematic equation. Any clue?
- #6
Hootenanny
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Sounds goot to me
- #7
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assume a level ground with no atmospheric resistance.
time of flight for the first half (rising) is t = (v-u)/g = 0.666 sec, sot he time of flight for the last half descent is also 0.666 sec. Total time is thus 1.333 sec.
with no reistance to motion in the x-axis the distance traveled is just the (X component of velocity) x time, do you know the angle?
time of flight for the first half (rising) is t = (v-u)/g = 0.666 sec, sot he time of flight for the last half descent is also 0.666 sec. Total time is thus 1.333 sec.
with no reistance to motion in the x-axis the distance traveled is just the (X component of velocity) x time, do you know the angle?