Equatorial Velocity of Electron: Find v for r=5*10^(-17)m

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In summary, the conversation discusses finding the equatorial velocity of an electron that is assumed to be a uniform sphere with a radius of 5*10^(-17) m and rotating about its center. The participants also consider the possibility of the electron having a magnetic moment of \hbar/2 and discuss how the magnetic moment of the spinning sphere is linked to the electron's spin. The question is further clarified and the participants thank each other for their contributions.
  • #1
asdf1
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for the following problem:
find the equatorial velocity v of an electron under the assumption that it is a uniform sphere of radius r=5*10^(-17) m that is rotating about an axis through its center.

how do you start thinking for that one?
 
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  • #2
Do you assume it is spinning such that it has a magnetic moment of [itex]\hbar/2[/itex] ?
 
  • #3
what do you mean? @@
 
  • #4
You assume the electron is a uniformly charged sphere with charge -e. Then finding the equatorial velocity means finding how fast the electron would be spinning right? I assume you have to link the magnetic moment of the spinning sphere to that of the electron (i.e. its spin).

Why don't you post the whole question along with the context in which we should consider it. And also what you have done so far.
 
  • #5
:P
that is the whole question...
how'd you think of linking the magnetic moment of the spinning sphere to that of the electron ?
 
  • #6
Well, what other physical property would you link it to? An electron has charge and spin.
 
  • #7
haha... you're right~ thank you very much!
 

1. What is the equation for finding the equatorial velocity of an electron?

The equation for finding the equatorial velocity of an electron is v = (1/2π) * (e/m) * (r^2 / r), where v is the velocity, e is the charge of an electron, m is the mass of an electron, and r is the radius of the electron's orbit.

2. How is the equatorial velocity of an electron related to its orbit radius?

The equatorial velocity of an electron is directly proportional to its orbit radius. This means that as the orbit radius increases, the equatorial velocity also increases.

3. What is the value of e/m in the equation for equatorial velocity calculation?

The value of e/m in the equation for equatorial velocity calculation is known as the specific charge and has a value of 1.76 * 10^11 C/kg for electrons.

4. How do I convert the given radius of 5*10^(-17)m to meters?

To convert the given radius of 5*10^(-17)m to meters, you simply need to move the decimal point 17 places to the left, resulting in a radius of 0.00000000000000005 meters.

5. Can the equation for equatorial velocity of an electron be used for other particles?

Yes, the equation for equatorial velocity of an electron can also be used for other particles as long as the specific charge (e/m) is known. However, the specific charge may be different for different particles.

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