A 1.00L vessel contains at equilibrium 0.300 mol of [itex]N_2[/itex], 0.400 mol [itex]H_2[/itex] and 0.100 mol [itex]NH_3[/itex]. If the temp is maintained constant, how many moles of [itex]H_2[/itex] must be introduced into the vessel in order to double the equilibrium concentration of [itex]NH_3[/itex](adsbygoogle = window.adsbygoogle || []).push({});

I said that if I let the change in conc. of [itex]H_2[/itex] be equal to x, then the change in conc. of [itex]\[NH_3\][/itex] would be 2/3x (from the chemical equation). Can't I just equation 2/3x with 0.100? It just seems too easy...

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# Homework Help: Equilibrium Concentration

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