• Support PF! Buy your school textbooks, materials and every day products Here!

Equilibrium Concentration

  • Thread starter ada15
  • Start date
  • #1
24
0

Homework Statement



CO(g) + NH_3(g) ...> HCONH_2(g)

euilibrium constant is: K = 0.207 at 400 K
If a reaction is filled with intial concentrations 2.20 M of CO and 2.60 M of NH_3 and the reactanats are allowed to raect at 400K/ what will be the concentrations of CO at equilibrium ?


Homework Equations



Keq = [HCONH_2] / [CO] [NH_3]

The Attempt at a Solution




0.207 = (X) /(2.20-X)(2.6-X)

But I'm getting the wrong answer for x. Please help me.
 

Answers and Replies

  • #2
16
0
^your equation for x seems correct. i rearranged it to
0 = 5.72/x - 5.007 + x
we need to find the zeroes

when graphed, the zeros are 1.76 and 3.24

if we use 3.24, we would have a negative concentration of both CO and NH3, which is physically impossible. so, we go with 1.76

so the answer: 2.2 M - 1.76 = 0.44 M
 

Related Threads on Equilibrium Concentration

  • Last Post
Replies
3
Views
990
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
9
Views
3K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
2
Views
3K
Replies
5
Views
3K
  • Last Post
Replies
5
Views
1K
  • Last Post
Replies
2
Views
3K
  • Last Post
Replies
3
Views
712
Replies
1
Views
3K
Top