Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Equilibrium constant from thermodynamic values

  1. Mar 23, 2007 #1
    1. The problem statement, all variables and given/known data
    Using information from tables, calculate the equilibrium constant K of the following reaction at 32 degrees C.

    [tex]PCl_5 \rightarrow PCl_3 + Cl_2[/tex]
    [tex]\Delta H^0_{rxn} = 68.6kJ[/tex]

    a) [tex]4.62 \times 10^{-3}[/tex]atm
    b) 216 atm
    c) [tex]7.81 \times 10^{-11}[/tex]atm
    d) 163 atm

    2. Relevant equations

    [tex] \Delta G^0 = -RT\ln{K_p}[/tex]
    [tex] \Delta G^0 = \Delta H^0 - T\Delta S^0[/tex]

    3. The attempt at a solution

    First attempt:

    Calculated the change in Gibbs energy using the energy of formation of the compounds, then plugged into the first equation to get Kp. Wrong answer.

    [tex] \Delta G^0 = 0 + (-267.8\frac{kJ}{mol}) - (-305\frac{kJ}{mol}) = 37.2kJ[/tex]
    [tex]K_p = e^{\frac{-37200J}{8.3145(305K)}} = 4.289 \times 10^{-7}[/tex]

    Second attempt:

    Calculated the change in entropy using values from tables, plugged into 2nd equation to get change in Gibbs, then plugged into first equation to get Kp. Wrong answer.

    [tex] \Delta S^0 = 223.08\frac{J}{Kmol} + 311.78\frac{J}{Kmol} - 364.58\frac{J}{Kmol} = 170.28\frac{J}{K}[/tex]
    [tex]\Delta G^0 = 68600J - (305K)(170.28\frac{J}{K}) = 16664.6J[/tex]
    [tex]\Delta K_p = 1.4 \times 10^{-3}[/tex]

    As usual, I'm going nuts. Any help appreciated.
     
    Last edited: Mar 23, 2007
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted