(adsbygoogle = window.adsbygoogle || []).push({}); 1. There is a block parallel and touching a vertical wall, a force F is applied at a 40 deg. angle from -x,-y. the weight of the block is 88.9N. The coefficient of static friction between the block and the wall is 0.560.

a) what is the minimum force F required to prevent the block from sliding down the wall?

b) what is the minimum force F required to start the block moving up the wall?

2. Relevant equations

3.a) Fs(max)=(0.560)(88.9N)=49.8N

Fy=88.9N-49.8N=39.1N

Fx=(39.1N)/(cos(40))=51.0N

[tex]\sqrt{39.1^2+51.0^2}[/tex]=F

F=64.3N

b) 88.9N +49.8 N=138.7N=Fy

Fx=(138.7N)/(cos(40))=181.06N

[tex]\sqrt{138.7^2+181.06^2}[/tex]=F

F=228N

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# Homework Help: Equilibrium/friction problem

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