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Homework Help: Equilibrium position

  1. Apr 17, 2014 #1
    I want to ask how will the equilibrium position of the system change if water is added to the system? ImageUploadedByPhysics Forums1397780805.704254.jpg
  2. jcsd
  3. Apr 17, 2014 #2
    Co^2+(aq.) + 4cl^-1(aq.) =cocl4^2-(aq.)
  4. Apr 17, 2014 #3
    The concentration will decrease because the volume will increase. This will make Q lower than the K value so the forward reaction should be favored(shifts right)
  5. Apr 18, 2014 #4
    Will the value of Q become smaller the K if the concentration is lower?
  6. Apr 18, 2014 #5
    *become greater
  7. Apr 18, 2014 #6
    Can you rephrase your question, I'm not sure I understand.
  8. Apr 18, 2014 #7


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    Staff: Mentor

    Quite the opposite, the more diluted the solution, the more dissociated the complex is.
  9. Apr 18, 2014 #8
    By adding water the rate of the forward reaction decreases X to the power 2 times while the rate of the backward reaction will decrease only X times so the reaction moves backwards
  10. Apr 18, 2014 #9
    Pretend the Keq is 1, and all species' molarity is 1 at the equilibrium. Now do the dilution recalculate Q based on the new concentrations. Compare Q with Keq and reason it out.
  11. Apr 20, 2014 #10
    And according to Ostwald's law : degree of dissociation increases by increasing dilution
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