- #1

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How long is required for the load to reach its equilibrium position?

T=2pi(square root(m/k))=.628s

Please verify to see if I did it correctly.

Thanks

- Thread starter timtng
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- #1

- 25

- 0

How long is required for the load to reach its equilibrium position?

T=2pi(square root(m/k))=.628s

Please verify to see if I did it correctly.

Thanks

- #2

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- #3

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so the answer should be T/4?

- #4

HallsofIvy

Science Advisor

Homework Helper

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- #5

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so t should equal to .628s/4 = .157 s

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