- #1

- 25

- 0

How long is required for the load to reach its equilibrium position?

T=2pi(square root(m/k))=.628s

Please verify to see if I did it correctly.

Thanks

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter timtng
- Start date

- #1

- 25

- 0

How long is required for the load to reach its equilibrium position?

T=2pi(square root(m/k))=.628s

Please verify to see if I did it correctly.

Thanks

- #2

- 1,589

- 3

- #3

- 25

- 0

so the answer should be T/4?

- #4

HallsofIvy

Science Advisor

Homework Helper

- 41,847

- 966

- #5

- 25

- 0

so t should equal to .628s/4 = .157 s

Share: