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Equilibrium Potential of Half Cell

1. Homework Statement
Given the following half-reactions:
Ce4+ + e− → Ce3+ E° = 1.72 V
Fe3+ + e− → Fe2+ E° = 0.771 V

A solution is prepared by mixing 9.0 mL of 0.30 M Fe2+ with 7.0 mL of 0.11 M Ce4+.

1. What is the potential of a platinum electrode dipped into the resulting, equilibrated, solution (relative to SHE)?

2. Calculate Keq for the reaction

Ce4+ + Fe2+ ⇌ Ce3+ + Fe3+

3. Calculate [Ce4+] in the solution.

2. Homework Equations

Nernst equation

3. The Attempt at a Solution

I got question 2 since its K = 10^(nEo/0.05916), K= 10^(1(1.72-0.771))/0.05916)=1.1*10^16

I tried and can't seem to get #1 correct. #3 I used ICE table method but cannot get a answer that makes sense. Any help is appreciated. Thanks.
 

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