A reaction mixture initially contains 2.24 atm Xe and 4.27 atm F2. If the equilibrium pressure of Xe is 0.34 atm, determine Kp for the reaction. This question came out of the blue, and all I can think of is that Kp=(PXe)(PF2), but the answer is supposed to be 25. I don't get it? Any suggestions? Thanks!