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Equilibrium Problem

  1. Nov 14, 2008 #1
    1. The problem statement, all variables and given/known data
    Basically, the string is attached a to a wall at the top right, with a mass m hanging on the other end. It asks to find the max mass m that can hang before bottom of the rod slips.

    2. Relevant equations

    3. The attempt at a solution
    I know that Ft=mg for the hanging mass m.
    Then for the x forces on the rod: Ft=Ffs
    so usFn=mg
    But I don't know what to do with the angle 50 degrees. You have to include it somewhere right?
    I was thinking us(50)(9.8)(sin50)=m(9.8) but I don't know if that's right.


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    Last edited: Nov 14, 2008
  2. jcsd
  3. Nov 15, 2008 #2


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    Welcome to PF.

    There are also torques to consider, which must sum to zero. (The angle will play a role here.)

    Also, while the tension in the vertical section of string is mg, in the horizontal section it can be something different.
  4. Nov 15, 2008 #3
    I was thinking about the torque, but don't you need to know the length of the rod to find them?
  5. Nov 15, 2008 #4


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    Let the rod length be L, and see how the torque equation works out.
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