1. The problem statement, all variables and given/known data A 60 kg tight-rope walker carries a long beam with a mass of 30 kg across a 10 m long wire. When she is at the centre of the wire (i.e. 5 m across), each section of the wire makes an angle of 5° to the horizontal. Assuming that the mass of the wire is negligible, calculate the tension within it. I would like to know if my process is right. I took forever just trying to figure out the problem and would like to verify that my process is correct or if there any omissions I may have left out. 2. Relevant equations T=rf Sum of the forces = 0 Sin=0 / H 3. The attempt at a solution Sum of the forces = 0 F(Tightrope walker) + F(Beam) = F(Tension in one half of the rope) + F(Tension in the other half) (60x9.8) + (30x9.8) = F(T1) + F(T2) 822=F(T1) + F(T2) 882 / (2 x Sin5 x 5) = 1011.98 1011.98 / 2 = 505.98 = 506 N <~ My answer is right, I checked in the answers section from the book.