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Equilibrium Question

  1. Jun 21, 2009 #1
    1. The problem statement, all variables and given/known data
    Picture: http://www.webassign.net/grr/p8-34.gif

    A mountain climber is rappelling down a vertical wall. The rope attaches to a buckle strapped to the climber's waist 15 cm to the right of his center of gravity and makes an angle of [tex]\theta[/tex]= 19° with the wall. The climber weighs 744 N.

    (a) Find the tension in the rope=680N
    (b) Find the magnitude and direction of the contact force exerted by the wall on the climber's feet.

    Magnitude=240N
    Direction=[tex]\theta[/tex]=? above the horizontal.

    2. Relevant equations
    T=[tex]\frac{W*.91m}{1.06m*cos19}[/tex]

    W=Tcos[tex]\theta[/tex]+F[tex]_{v}[/tex]

    T*sin[tex]\theta[/tex]=F[tex]_{h}[/tex]

    Magnitude F[tex]_{w}[/tex]=[tex]\sqrt{F^{2}_{v}+F^{2}_{h}}[/tex]

    3. The attempt at a solution
    The equations basically explain my attempt at the problem. I just can't seem to be able to find the direction of the contact force exerted by the wall.

    I've tried:
    arctan[tex]\frac{Fv}{Fh}[/tex]=25°
     
  2. jcsd
  3. Jun 21, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    Welcome to PF.

    I get roughly what you are getting. What seems to be telling you it is wrong? (I get 244 N at 25.5 degrees above the horizontal.)

    The wall is pushing up - countering the weight not made up in the tension, and out against the compression of the feet.
     
  4. Jun 21, 2009 #3
    Ah I got it. It was a significant digits thing.

    the acceptable answer was 26.

    Thanks for your help!
     
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