An insulated bucket contains 150 g of ice at 0°C. If 26.0g of steam is injected at 100°C into the bucket, what is the final equilibrium temperature of the system in °C?(adsbygoogle = window.adsbygoogle || []).push({});

this i what ive done so far

q(ice)=150g*333.5J/g=50025J

q(steam)=26g*2257J/g=58682J

q(ice) + q(ice-water) = -[q(steam) + q(steam-water)]

50025J + 4.18J/g*150g(Tf-273)=-[58682J + 4.18J/g*26g(Tf-373)]

20025J + 327J*Tf - 171171J = -58682J -108J*Tf + 40538J

-121146J + 627J*Tf = -18145 - 108J*Tf

735J*Tf=103002

Tf=140degree K

this is obviously wrong....what am i missing?

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# Homework Help: Equilibrium temperature

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