(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A beam resting on two pivots has a length ofL = 6.00 mand massM = 72.0 kg. The pivot under the left end exerts a normal force n1 on the beam, and the second pivot placed a distancel = 4.00 mfrom the left end exerts a normal force n2. A woman of massm = 51.1kg steps onto the left end of the beam and begins walking to the right as in the figure below. The goal is to find the woman's position when the beam begins to tip.

[PLAIN]http://www.webassign.net/sercp8/p8-12.gif[/IMG [Broken]

a. What is n1 when the beam is about to tip?

b. Use the force equation of equilibrium to find the value of n2 when the beam is about to tip.

c. Using the result of part (a) and the torque equilibrium equation, with torques computed around the second pivot point, find the woman's position when the beam is about to tip.

3. The attempt at a solution

a.n1=0 N

b. n2=mg

n2= (51.1kg)(9.8 m/s^{2})

n2=500.78 N

c. since F is 0 in part a, I would think that this answer will be zero as well

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# Homework Help: Equilibruim: pivot points

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