1. The problem statement, all variables and given/known data A 20.00 ml stock sample of HBr is diluted to 50 mL. If 18.76 ml of 0.1345 M KOH was required to reach the equivalence point, what is the concentration of the stock HBr solution? 2. Relevant equations KOH + HBr --> KBr + H20 M = conc. = mol./L n = V * conc. 3. The attempt at a solution n-KOH= V-KOH * conc. KOH = (18.76*10^-3 L) * (0.1345 mol./L) = (2.52322*10^-3 mol.) => n-HBr= (2.52322*10^-3 mol.) V-HBr= 5.0*10^-4 L conc. HBr = (2.52322*10^-3 mol.)/ (5.0*10^-4 L) = 5.04644 M I dont think this the right answer but I seem to endup with the right units, can someone please tell me what I am doing wrong and how to go about this question the right way?