# Equivalence Relations proof

1. Sep 19, 2009

### jeff1evesque

Statement:
Prove or Disprove: A relation ~ on a nonempty set A which is symmetric and transitive must also be reflexive.

Ideas:
If our relation ~ is transitive, then we know: a~b, and b~a $$\Rightarrow$$ a~a.
Therefore our relation ~ is reflexive, since b~c and c~b $$\Rightarrow$$ b~b, and c~a and a~c $$\Rightarrow$$ c~c.

Proof:
Can the above (idea) constitute a proof in itself?

Thanks,

Jeffrey

2. Sep 19, 2009

### jeff1evesque

Actually I thought about it a little, and came up with a proof. But can someone critique it and let me know if it's actually alright.

Proof
We know ~ is symmetric.
Therefore, $$\exists a,b,c \in A$$ such that
if a~b, then b~a,
and if b~c, then c~b,
and if c~a, then a~c.​
But we also know our relation ~ is transitive.
Therefore,
if a~b, and b~a, then a~a, (#1)
and if b~c, and c~b, then b~b, (#2)
and if c~a, and a~c, then c~c. (#3)​
By (#1), (#2), and (#3) we know our given relation is reflexive.