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Equivalent capacitance; complex circuit

  1. Nov 5, 2008 #1
    1. The problem statement, all variables and given/known data

    Hello, I was given this problem as a homework assigment.
    Each capacitor in the figure has capacitance C. What is the equivalent capacitance between points a and b?
    The answer is given in "C_eq/C"

    [​IMG]

    2. Relevant equations

    I used the "C_eq={(1/C_1)+(1/C_2)+.....(1/C_n)}^-1" for the capacitors in series.
    I used the "C_eq=(C_1)+(C_2)+.....(C_n) for the capacitors in parallel.

    3. The attempt at a solution

    Combining everything that was in parallel and everything that was in series until it come down to one capacitor, the answer that i get is C or 1. Any ideas on what I am doing wrong or if im inputing the answer in the wrong way?
     

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    Last edited: Nov 5, 2008
  2. jcsd
  3. Nov 5, 2008 #2

    Redbelly98

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    Staff Emeritus
    Science Advisor
    Homework Helper

    Welcome to PF.

    It may be just me, but I don't see any series capacitors in this circuit.

    This one may require Kirchoff's loop and node laws (also known as KVL and KCL).
     
  4. Nov 5, 2008 #3
    I think it is 2C.
    If you consider capacitors like resistances, you will see bridge and one of the capacitor behaves as open circuited.
     
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