# Equivalent capacitance; complex circuit

1. Nov 5, 2008

### quietriot1006

1. The problem statement, all variables and given/known data

Hello, I was given this problem as a homework assigment.
Each capacitor in the figure has capacitance C. What is the equivalent capacitance between points a and b?
The answer is given in "C_eq/C"

2. Relevant equations

I used the "C_eq={(1/C_1)+(1/C_2)+.....(1/C_n)}^-1" for the capacitors in series.
I used the "C_eq=(C_1)+(C_2)+.....(C_n) for the capacitors in parallel.

3. The attempt at a solution

Combining everything that was in parallel and everything that was in series until it come down to one capacitor, the answer that i get is C or 1. Any ideas on what I am doing wrong or if im inputing the answer in the wrong way?

#### Attached Files:

• ###### 30_CP86.jpg
File size:
4.3 KB
Views:
309
Last edited: Nov 5, 2008
2. Nov 5, 2008

### Redbelly98

Staff Emeritus
Welcome to PF.

It may be just me, but I don't see any series capacitors in this circuit.

This one may require Kirchoff's loop and node laws (also known as KVL and KCL).

3. Nov 5, 2008

### tanerr

I think it is 2C.
If you consider capacitors like resistances, you will see bridge and one of the capacitor behaves as open circuited.