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Equivalent Capacitance

  1. Nov 3, 2009 #1
    1. The problem statement, all variables and given/known data
    What is the equivalent capacitance of the arrangement shown in figure. (Answer is C1)


    2. Relevant equations
    Cparallel = C1+C2+...Cn
    Cseries = 1/(1/C1+1/C2+...+1/Cn)


    3. The attempt at a solution
     

    Attached Files:

  2. jcsd
  3. Nov 3, 2009 #2

    Andrew Mason

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    It is easier to see what is happening if you change the drawing to a square with 2 C1s on each side in series and a C2 attached across the middle (from points between the C1s).

    By the symmetry of the circuit, you can see that there is 0 voltage across the C2 capacitor. So the C2 really does nothing to change the capacitance of the circuit - ie. it never stores charge. So the capacitance is the same as the circuit without C2.

    AM
     
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