# Equivalent capacitance

1. Nov 14, 2012

### KeithLucas

1. The problem statement, all variables and given/known data

I'm trying to find the equivalent capacitance for a circuit, but I keep getting stuck.

2. Relevant equations
C(parallel)=C1+C2+...Cn
C(series)={(1/C1)+(1/C2)+(1/C3)+...(1/Cn)}^-1

3. The attempt at a solution
See the first penciled attachment.

#### Attached Files:

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• ###### CCF11142012_0002.jpg
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2. Nov 14, 2012

### superdave

I would start by solving everything that is in series with no junctions in between. That should clean it up a bit. If you still have trouble, post your drawing again after doing that.

3. Nov 14, 2012

### KeithLucas

Which ones are in series with no junctions in between? I've posted the original circuit in one attachment, but another attachment has my attempt where I thought I solved everything in series.

4. Nov 14, 2012

### haruspex

Top and top left.

5. Nov 14, 2012

### bsbs

your penciled attempt work out to be 3μF, which is same as mine and i think it is correct.

Last edited: Nov 14, 2012