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Forums
Engineering
Electrical Engineering
Equivalent circuit of an Induction Motor
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[QUOTE="Babadag, post: 5419620, member: 407262"] The dynamic circuit it is not actually a circuit but a symbolic "like" circuit. The dynamic diagram is referring to space vector [all three phases in matrix form] and connected with Laplace transform [“p” or ” s” noted]. It facilitates to find the Laplace transform for a circuit where instead of derivate it will be p and instead of integral 1/p. In order to find the actual values you have to integrate the result according to Laplace transform rules. If you'll write the voltage drops on stator circuit and rotor circuit you’ll get: Vs s = Rs Is s + p λs s stator circuit 0 = Rr*Ir s + (p - jωo) λr s rotor circuit where: λs s = Ls Is s + Lm Ir s and λr s = Lm Is s + Lr Ir s Since Laplace transform is an integral you have to consider the limits and the lower limit is rotor velocity [wo=wr].So jωo λr s= jωrΨs See: [URL]http://mathworld.wolfram.com/LaplaceTransform.html[/URL] [URL]http://www.drivetechinc.com/articles/IM98VC1.pdf[/URL] [URL]http://lipo.ece.wisc.edu/1994pubs/94-14T.pdf[/URL] [/QUOTE]
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Engineering
Electrical Engineering
Equivalent circuit of an Induction Motor
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