Equivalent circuit?

Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/ [Broken]

as this
http://postimg.org/image/uvtf6f8vv/ [Broken]


?
 
Last edited by a moderator:

BvU

Science Advisor
Homework Helper
11,557
2,494
Hello, your higness. Not your first post, so you should know better by now. Use the template and don't make me chase links instead of going to sleep. Maybe tomorrow.

But, out of curiosity: is the central point in the first picture a connection or is I1 = -I3 ?
 

lewando

Homework Helper
Gold Member
1,313
118
Whether the central point is connected or not, the redrawing is not correct. One discrepancy (and there are others): in the original drawing, the 4 Ω and the 6 Ω share a node. In the redrawing, they do not.
 

SammyS

Staff Emeritus
Science Advisor
Homework Helper
Gold Member
11,029
845
Just wondering if its ok to re-draw this
http://postimg.org/image/a074v6cor/ [Broken]

as this
http://postimg.org/image/uvtf6f8vv/ [Broken]

?
No


attachment.php?attachmentid=66728&stc=1&d=1392691615.png


Is not the same as

attachment.php?attachmentid=66729&stc=1&d=1392691712.png


Your circuit would force I3 = -I2

and I1 = 1 Amp
 

Attachments

Last edited by a moderator:
1,845
169
It would be correct if you add a wire from the point between the 4 and 12 ohm resistors at the bottom to the point between the 6 ohm resistor and the 1 amp current source at the top. You separated the 4 wires coming together in the midpoint into 2 pairs.
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving

Members online

Top