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Equivalent forces in Statics.

  1. Jan 15, 2012 #1
    1. The problem statement, all variables and given/known data

    X3ygx.png

    Replace the force for by the equivalent of two forces paralel at the dot and the other perpendicular to the beam.

    The force P is 2000 N

    Determine the forces!


    2. Relevant equations

    Fx= P*cos(x) =
    Fy= P*sin(x) =

    3. The attempt at a solution

    Fx= 2000 N* cos(75)= 0.517 kN
    Fy= 2000 N* sin(75) = 1.93 kN


    Am I on the right track? It's just the angle that i'm not sure about.
     
  2. jcsd
  3. Jan 15, 2012 #2
    Does this look right?
     

    Attached Files:

  4. Jan 15, 2012 #3
    Yes. This looks better. I cant believe i didn't think to check on what Pythagoras thought about my solution.

    Thank you!
     
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