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Equivalent impedance

  1. Jan 6, 2016 #1
    1. The problem statement, all variables and given/known data
    Hi everyone, I'm just having a little trouble with equivalent resistance in a bridge, in the image I attached. The textbook says that the way to solve this is to put R3 and ZL2 in series, that series is in parallel to the short circuit in diagonal, and then at the end we have a parallel between:

    1 Zc

    2 The series between R1 and the parallel zl1 and R2.

    The point is, I can't understand why it puts zl2 and r3 in series, when they're divided by a clamp.


    2. Relevant equations



    3. The attempt at a solution
    My reasoning was, instead, to put R3 in parallel with zl2. We have a parallel also between Zl1 and R2. Then we solve the circuit with the usual methods Resistenze.png Resistenze.png Resistenze.png
     
    Last edited by a moderator: Jan 6, 2016
  2. jcsd
  3. Jan 6, 2016 #2

    gneill

    User Avatar

    Staff: Mentor

    Your approach looks better. Presuming that you want the equivalent impedance between terminals A and B, then R3 and ZL2 cannot be in series since terminal B attaches to one node where they join, and several other components meet at the other node where they join.
     
  4. Jan 7, 2016 #3
    Yes, the impedance that I have to calculate is between the terminals A and B
     
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