# Equivalent resistance

Hi guys,I'm new here and maybe I'm posting this homework in a wrong part of the forum.I tried to find the equivalent resistance.It may be a simple homework but im learning first for the electricy physic.I tried to find Re first R2+R3=4 Ω and than found Re=1/4 Ω + 1/2 Ω + 1/2 Ω can i slove it this way? (P.s sorry for my bad english.)

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ehild
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Hi guys,I'm new here and maybe I'm posting this homework in a wrong part of the forum.I tried to find the equivalent resistance.It may be a simple homework but im learning first for the electricy physic.I tried to find Re first R2+R3=4 Ω and than found Re=1/4 Ω + 1/2 Ω + 1/2 Ω can i solve it this way? (P.s sorry for my bad english.)

R1 is not parallel with the resultant of R2, R3, R4. Check.

ehild

Can it be formed so?

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ehild
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Can it be formed so?
Yes. ehild

Yes. ehild
Then I did it so:R23=2Ω +2Ω =4Ω and 1/Re=1/4Ω + 1/2Ω +1/2Ω = 5/4Ω Re=4Ω /5? Is this the right way of slowing it?

ehild
Homework Helper
Then I did it so:R23=2Ω +2Ω =4Ω and 1/Re=1/4Ω + 1/2Ω +1/2Ω = 5/4Ω Re=4Ω /5? Is this the right way of solwing it?
No. What does parallel connection mean? Explain which resistors are connected in series and which are parallel.

ehild

R2,R3 are connected in series.And R4 R1 in paralel?

R2,R3 are connected in series.
Yes.

Dr.Phy said:
And R4 R1 in paralel?
No. The equivalent resistance of R2 and R3 is in parallel with R4. Do you see why?

Yes.

No. The equivalent resistance of R2 and R3 is in parallel with R4. Do you see why?
Yes but i dont know how is it connected the R1,and how to find the eq reasistance of this circuit can u help me :/ .

Yes but i dont know how is it connected the R1,and how to find the eq reasistance of this circuit can u help me :/ .
Draw figures after each reduction. R2 and R3 are in series as you said. Replace them with a single resistor and draw the figure.