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Equivalent resistance

  1. Jan 16, 2013 #1
    Hi guys,I'm new here and maybe I'm posting this homework in a wrong part of the forum.I tried to find the equivalent resistance.It may be a simple homework but im learning first for the electricy physic.I tried to find Re first R2+R3=4 Ω and than found Re=1/4 Ω + 1/2 Ω + 1/2 Ω can i slove it this way? (P.s sorry for my bad english.)
     

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  3. Jan 16, 2013 #2

    ehild

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    R1 is not parallel with the resultant of R2, R3, R4. Check.

    ehild
     
  4. Jan 16, 2013 #3
    Can it be formed so?
     

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  5. Jan 16, 2013 #4

    ehild

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    Yes. :smile:

    ehild
     
  6. Jan 17, 2013 #5
    Then I did it so:R23=2Ω +2Ω =4Ω and 1/Re=1/4Ω + 1/2Ω +1/2Ω = 5/4Ω Re=4Ω /5? Is this the right way of slowing it?
     
  7. Jan 17, 2013 #6

    ehild

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    No. What does parallel connection mean? Explain which resistors are connected in series and which are parallel.


    ehild
     
  8. Jan 17, 2013 #7
    R2,R3 are connected in series.And R4 R1 in paralel?
     
  9. Jan 17, 2013 #8
    Yes.

    No. The equivalent resistance of R2 and R3 is in parallel with R4. Do you see why?
     
  10. Jan 17, 2013 #9
    Yes but i dont know how is it connected the R1,and how to find the eq reasistance of this circuit can u help me :/ .
     
  11. Jan 17, 2013 #10
    Draw figures after each reduction. R2 and R3 are in series as you said. Replace them with a single resistor and draw the figure.
     
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