i have 5 values of slit width S(adsbygoogle = window.adsbygoogle || []).push({});

0.0015m

0.0158m

0.00191m

0.0021m

0.00257m

the standard error is plus or minus 0.0005

however my teacher says she wants us to calculate ∆S error

she says its ∆S=S(subscript 2) - S(subscript 1)

she says the answer is 0.0007m

WHY IS THIS SO?

Fabian

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# Error analysis

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