Error due to the arrangement of conditions with an IF statement in while loop with an AND operator

• Python

Summary:

I am slightly confused as to why, in a IF statment that when using the AND operator the order in which the operator matters.

Main Question or Discussion Point

I am currently doing a leet code problem and came across something, I have not noticed before.

Here is a sample of the code I am working on.

Python:
s = "10#11#12"
A=[]
B=[]
i=0
count=0
while i < len(s):
if i+2<len(s) and s[i+2]=='#':
A+=[(s[i]+s[i+1]+s[i+2])]
i+=3
print(i)
Now the code above throws no error, however when I change the order of the and statment like the code below:

Python:
s = "10#11#12"
A=[]
B=[]
i=0
count=0
while i < len(s):
if s[i+2]=='#' and  i+2<len(s) :
A+=[(s[i]+s[i+1]+s[i+2])]
i+=3
print(i)
I get an out of range error as shown below:
Traceback (most recent call last):
File "<string>", line 10, in <module>
IndexError: string index out of range
So my question is why does order matter? I have always been under the impression that if you had an and statement with two True conditions then it would carry through the if statement, and if one of the conditions was False did not matter which way round it was it would not carry through the if statement.

I now assume this type of thinking is wrong.

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Ibix
Many (not all) languages implement "shortcut" evaluation of if conditions. If you do a test like IF A AND B THEN, and it turns out that A is FALSE, then there's no point in even checking B - we know A AND B is FALSE whatever it is. So the computer can shortcut the operation. Ditto A OR B if A is TRUE - there's no point checking B in this case.

Knowing this, can you see why your first version works and your second one errors out?

Ibix
Incidentally, is what you are trying to achieve here just A=s.split("#")? This isn't what your code does, but I suspect it might be what you are aiming at.

Many (not all) languages implement "shortcut" evaluation of if conditions. If you do a test like IF A AND B THEN, and it turns out that A is FALSE, then there's no point in even checking B - we know A AND B is FALSE whatever it is. So the computer can shortcut the operation. Ditto A OR B if A is TRUE - there's no point checking B in this case.

Knowing this, can you see why your first version works and your second one errors out?
Ah okay, I can see now thank you. Also, I am not aiming at splitting the given string. Basically I have to use a dictionary to convert there given string to a bunch of letter i.e decrypt the message, in this case, a-i is given the numbers 1-9 and j-z onwards is given by 10#, 11#,12#, etc.

I was just playing around with the idea of separating each of these into a list than checking against a dictionary, then from there looking at ways to optimize it the code.

Ibix
Ah - I see. You can definitely optimise that, but I'll leave you to explore.

A couple of points, though. First, s[i]+s[i+1]+s[i+2] can be written s[i:i+3]. That becomes a huge saving when you want s[i:i+50]! Second, can I suggest more descriptive variable names? s for string isn't bad, but encryptedString would be better. And almost anything is better than A and B. Perhaps encryptedChars and decryptedChars?

Side note - my phone's autocomplete dictionary has "encrypted" but not "decrypted". Weird...

Ah - I see. You can definitely optimise that, but I'll leave you to explore.

A couple of points, though. First, s[i]+s[i+1]+s[i+2] can be written s[i:i+3]. That becomes a huge saving when you want s[i:i+50]! Second, can I suggest more descriptive variable names? s for string isn't bad, but encryptedString would be better. And almost anything is better than A and B. Perhaps encryptedChars and decryptedChars?

Side note - my phone's autocomplete dictionary has "encrypted" but not "decrypted". Weird...
First thank for the input, I can't believe I didn't think of using a slice method, thank you. To be honest I am just doing the leetcode problems, not for interview practice but more to learn about the python language itself. Also yes I agree my variable names should be more descriptive make sure of this next time