1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Error estimation of moment of inertia of a flywheel

  1. Dec 10, 2004 #1
    now i get the formula I = mr^2 [n2/(n1+n2)] [(gt^2)/(2h) - 1]
    where m = mass of the hanging wieght; r = radius; n1 = no. of revolutions before the weight reaches the floor; n2 = no. of revolutions before the flywheel stops; t = time taken for the weight to reach the floor; h = height of which the weight had dropped.

    and i'm to calculate the % error of I.

    - what is the error of n1 and n2? 1 revolution??
    - in my practical book, before asking me to calculate the respective % error of all the variables, it states "since gt^2/2h >> 1, by approximation, % error of ..... = ...... ", what the actual meaning of this statement??
    - the formula of % error of I stated is the book is 2x<r> + <n1> + <n2> + 2x<t> + <h>, where <*> = % error of *. but i think % error of n2 should be multiplied by a 2, is this a mistake of me or the book??
  2. jcsd
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted