i've been trying to prove this question, but so far, there is no successs... http://members.shaw.ca/brian103/theerrorfunction.jpg
Does this help? [tex]\int_a^b = \int_a^0+ \int_0^b[/tex] [tex]\frac {d}{dx} \int_0^x f(x') dx' = f(x)[/tex]
a. Use the additive property of definite integral. [tex]\int _0^bf(t)dt=\int_0^af(t)dt+\int_a^bf(t)dt [/tex] b. Remember that the differential quotient of definite integral with respect to the upper bound is the integrand itself. [tex] \big[\int _0^xf(t)dt\big]' = f(x)[/tex] ehild