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Python Error of execution

  1. Sep 8, 2016 #1
    I am trying to scrape some website. And this the code i have
    Code (Python):

    import urllib2
    from bs4 import BeautifulSoup
    from urllib import URLopener
    from urllib import FancyURLopener
    import traceback,sys

    headers = {
        'Origin': '[URL]http://www.nrega.nic.in/netnrega/home.aspx[/URL]',
        'User-Agent': 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.17 (KHTML, like Gecko)  Chrome/24.0.1312.57 Safari/537.17',
        'Content-Type': 'application/x-www-form-urlencoded',
        'Referer': '[URL]http://mnregaweb4.nic.in/netnrega/all_lvl_details_dashboard_new.aspx[/URL]',
        'Accept-Encoding': 'gzip,deflate,sdch',
        'Accept-Language': 'en-US,en;q=0.8',
        'Accept-Charset': 'ISO-8859-1,utf-8;q=0.7,*;q=0.3'
    class MyOpener(FancyURLopener, object):
        version = 'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.57 Safari/537.17'

    myopener = MyOpener()
    url = myopener.retrieve('[URL]http://mnregaweb4.nic.in/netnrega/all_lvl_details_dashboard_new.aspx[/URL]')
    # first HTTP request without form data
    f = urllib2.urlopen(url)
    def run_user_code(envdir):
        source = raw_input(">>> ")
        exec source in envdir
            print "Exception in user code:"
            print '-'*60
            print '-'*60

    envdir = {}
    while 1:
    soup = BeautifulSoup(f)
    # parse and retrieve two vital form values
    viewstate = soup.findAll("input", {"type": "hidden", "name": "__VIEWSTATE"})
    eventvalidation = soup.findAll("input", {"type": "hidden", "name": "__EVENTVALIDATION"})

    print viewstate[0]['value']
    formData = (
         ('__EVENTVALIDATION', eventvalidation),
        ('__VIEWSTATE', viewstate),
        ('TextBox1', '106110006'),
        ('Button1', 'Show'),

    encodedFields = urllib2.urlencode(formData)
    # second HTTP request with form data
    f = myopener.open(url, encodedFields)
        # actually we'd better use BeautifulSoup once again to
        # retrieve results(instead of writing out the whole HTML file)
        # Besides, since the result is split into multipages,
        # we need send more HTTP requests
            fout = open('census.html','w')
            print('Could not open output file\n')
    But i m getting the error like
    Code (Text):

    Traceback (most recent call last):
      File "C:\Python27\nerga - Copy.py", line 25, in <module>
        f = urllib2.urlopen(url)
      File "C:\Python27\lib\urllib2.py", line 154, in urlopen
        return opener.open(url, data, timeout)
      File "C:\Python27\lib\urllib2.py", line 420, in open
        req.timeout = timeout
    AttributeError: 'tuple' object has no attribute 'timeout'
    Anyone can help in this

    Last edited by a moderator: Sep 8, 2016
  2. jcsd
  3. Sep 8, 2016 #2


    Staff: Mentor

  4. Sep 12, 2016 #3
    Thanks for your guidance but it's not working
  5. Sep 12, 2016 #4


    Staff: Mentor

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