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## Homework Statement

You have a cylindrical tube for which you know the length is 16±0.1 cm and the radius is 8±0.1 cm, what is the error of the volume?

## Homework Equations

## The Attempt at a Solution

V = π*8

^{2}*16 = 3216.99 cm

But since the r term is squared, must we account for its error twice in the error propagation equation?

σ

_{V}= 3216.99*√((0.1/16)

^{2}+(0.1/8)

^{2}+(0.1/8)

^{2}

Or does this require only one (0.1/8)

^{2}term?