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Error Propagation

  1. Jan 21, 2015 #1
    1. The problem statement, all variables and given/known data
    You have a cylindrical tube for which you know the length is 16±0.1 cm and the radius is 8±0.1 cm, what is the error of the volume?

    2. Relevant equations

    3. The attempt at a solution
    V = π*82*16 = 3216.99 cm

    But since the r term is squared, must we account for its error twice in the error propagation equation?

    σV = 3216.99*√((0.1/16)2+(0.1/8)2+(0.1/8)2

    Or does this require only one (0.1/8)2 term?
  2. jcsd
  3. Jan 21, 2015 #2


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