# Error terms in Taylor Series

1. Dec 16, 2008

### Nurdan

It is known that
$$\sum\limits_{k = 0}^\infty {\frac{{N^k }}{{k!}}} = e^N$$

I am looking for any asymptotic approximation which gives

$$\sum\limits_{k = 0}^M {\frac{{N^k }}{{k!}}} = ?$$
where $$M\leq N$$ an integer.

This is not an homework

2. Dec 16, 2008

### christianjb

I'm only being a little facetious if I point out that the sum is asymptotically equal to e^N.

Want more accuracy? It's better approximated by e^N-[x^(N+1)]/(N+1)!

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