# Escape Speed problem

Therefore, the final kinetic energy will always be positive and the particle will never escape the gravitational pull. This is a common mistake that can be avoided by properly understanding the concept of escape velocity. In summary, the escape velocity of a particle from the surface of a massive body is determined by the law of conservation of energy and the value of the first term in the equation \frac{1}{2}(mu^2) - \frac{GMm}{R} must always be greater than or equal to the second term \frac{GMm}{R}. A negative value for the first term indicates that the particle's initial velocity is too low to escape the gravitational pull and the final kinetic energy will always be positive.

Hi friends.

Somewhere in a reference book I read about escape speed of a particle for earth.
Let a particle is projected from the Earth surface. Let its mass be m and speed of projection be u. Let mass of Earth be M and its radius be R.

According to law of conservation of energy,
https://fbcdn-sphotos-a-a.akamaihd.net/hphotos-ak-prn2/q86/s720x720/1175485_1407193806174392_209657781_n.jpg
https://fbcdn-sphotos-g-a.akamaihd.net/hphotos-ak-prn2/q88/s720x720/1236159_1407193812841058_1152852378_n.jpg
The problem is that,

If the Ist term becomes negative also but its magnitude is less than the IInd term, then also final Kinetic energy will be positive. And the particle will never doesn't give the proper answer. Friend isn't it so?

The first term in what? You mean term I in the first relation?
That's kinetic energy - does it make physical sense to have a negative kinetic energy?

Simon Bridge said:
The first term in what? You mean term I in the first relation?
That's kinetic energy - does it make physical sense to have a negative kinetic energy?

The first term is in the second relation. the complete 1/2(mu2) - (GMm)R

The complete term can be negative due to less value of 1/2 (mu2).

For escape velocity you're comparing the total energy at the surface of a massive body and at infinity from it.

This means that the second term $\frac{GMm}{R+h}$ will always be zero. So the first term can not be less in magnitude than the second one.

If the first term becomes negative due to too low a value of initial velocity U, it simply means that the velocity U is too low to escape the gravity of the massive body.