If an object is thrown upwards with escape velocity, will it orbit the earth?
For a body launched from the surface of the earth the only possibility for a circular orbit is a horizontal launch with a speed equal to escape velocity divided by the square root of two. Any other direction and the orbit will intersect with the surface of the Earth. Any higher velocity and the orbit will fail to be circular. It will rise above the surface of the earth. Any lower velocity and the orbit will fail to be circular. It will fall below the surface of the earth.Will a body projected with a speed less than the escape velocity may orbit the earth in circular path?