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Estimate the percentage

  1. Sep 15, 2011 #1
    The center of a 1.30 km diameter spherical pocket of oil is 1.30 km beneath the Earth's surface.
    Estimate by what percentage g directly above the pocket of oil would differ from the expected value of g for a uniform Earth? Assume the density of oil is 8.10x10^3 kg/m^3

    Should I use the equation: F = G (m1 + m2) / r^2 ?
    If not, which equation should I use?

    Please help me to get started.

    Thank you.
  2. jcsd
  3. Sep 15, 2011 #2
    Does this seem right way to find g and g'?

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