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## Homework Statement

A small city requires about 19 MW of power. Suppose that instead of using high-voltage lines to supply the power, the power is delivered at 120 V .

Assuming a two-wire line of 0.60cm -diameter copper wire, estimate the cost of the energy lost to heat per hour per meter. Assume the cost of electricity is about 8.5 cents/kWh.

Cost = $ per hour per meter

## Homework Equations

P=IV

P=I^2*R

R=(rhoe*L)/A

## The Attempt at a Solution

I used P=IV to find the current (converting 19 MW to 19*10^3 to keep it in kW for the answer) and found I=158 A .. then when I go to find the resistance I figure to use pi*r^2 as area than multiply the whole thing by two for the two wires but I do not understand what to use for L because they provide no length after i find R i intend to plug it into the equation P=I^2*R .. i am so lost!