Eta particle

  • Thread starter yola
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  • #1
yola
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Why is the eta particle written as 1/sqrt(6) *(uu(bar) + dd(bar) -2ss(bar))?
Thanks
 

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  • #2
fzero
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Because that's a definite-weight state of [tex]SU(3)[/tex] flavor. And by definite-weight state I mean an eigenstate of specific [tex]SU(3)[/tex] generators (specifically what are called Casimir operators, the analog of [tex]\vec{J}^2[/tex] for [tex]SU(2)[/tex]). It's analogous to working out the product states of two spin 1/2 particles, but a little bit more complicated because the algebra of [tex]SU(3)[/tex] has more generators than [tex]SU(2)[/tex].
 
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  • #3
yola
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Can you please specify for me a reference to check?
Thanks
 
  • #4
fzero
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Howard Georgi, "Lie Algebras In Particle Physics" is a standard reference.
 
  • #5
yola
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Great, Thanks
 

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