- #1

yola

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Why is the eta particle written as 1/sqrt(6) *(uu(bar) + dd(bar) -2ss(bar))?

Thanks

Thanks

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- Thread starter yola
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- #1

yola

- 17

- 0

Why is the eta particle written as 1/sqrt(6) *(uu(bar) + dd(bar) -2ss(bar))?

Thanks

Thanks

- #2

fzero

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Because that's a definite-weight state of [tex]SU(3)[/tex] flavor. And by definite-weight state I mean an eigenstate of specific [tex]SU(3)[/tex] generators (specifically what are called Casimir operators, the analog of [tex]\vec{J}^2[/tex] for [tex]SU(2)[/tex]). It's analogous to working out the product states of two spin 1/2 particles, but a little bit more complicated because the algebra of [tex]SU(3)[/tex] has more generators than [tex]SU(2)[/tex].

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- #3

yola

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Can you please specify for me a reference to check?

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Thanks

- #4

fzero

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Howard Georgi, "Lie Algebras In Particle Physics" is a standard reference.

- #5

yola

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Great, Thanks

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