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Euclid's Algorithm

  1. Feb 12, 2008 #1
    1. The problem statement, all variables and given/known data

    [​IMG]


    3. The attempt at a solution

    pretty stuck...
     
  2. jcsd
  3. Feb 12, 2008 #2

    Dick

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    Look at 5 and 7. I cleverly observe that 3*5-2*7=1. Now any integer is a multiple of 1, right?
     
  4. Feb 12, 2008 #3
    yeah...
     
  5. Feb 12, 2008 #4
    ...go on...
     
  6. Feb 12, 2008 #5

    Dick

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    So n=(3*n)*5+(-2*n)*7. Doesn't that look like a linear combination of 5 and 7?
     
  7. Feb 12, 2008 #6
    :)

    great - thanks - i have got all the others now.
     
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