Euler-Lagrange Tensor Equations

  • #1
binbagsss
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I need to vary w.r.t ##a_{\alpha \beta} ##

##\frac{\partial L}{\partial_{\mu}(\partial_{\mu}{a_{\alpha\beta}})}-\frac{\partial L}{\partial {a_{\alpha \beta}}}## (1)

I am looking at varying the term in the Lagrangian of ##\frac{1}{3}A^{\mu} \partial_{\mu}\Phi ##

where ##A^{\beta}=\partial_k {a^{k\beta}} ##

##\frac{\partial L}{\partial_{\mu}(\partial_{\mu}{a_{\alpha\beta}})}-\frac{\partial L}{\partial {a_{\alpha \beta}}}##




My working


(Expect it to yield a corresponding term in the EoMs as: ##\frac{1}{3}\partial^m \partial^{n} \Phi-\frac{1}{4}\eta^{\alpha \beta} \partial^f \partial_f \Phi## [2] )


I don't think I've ever done this properly, so my apologies, but my guess is want to keep things as general as possible with the indicies in (1) and those used on the ##a_{\alpha \beta} ## tensor so (also, with the first term in (1)- is the index ##\mu## are they both supposed to be the same or is it better to keep it more general, something like:##\frac{\partial L}{\partial_{\nu}(\partial_{\mu}{a_{\alpha\beta}})}##?) :

## \frac{1}{3}A^{\mu} \partial_{\mu}\Phi= \frac{1}{3}\partial_c a^{c \mu} \partial_{\mu} \Phi, ##

So if I say I am varying it w.r.t ##\partial_{k}a^{mn}## for the first term of (1), (obviously second term of (1) not relevant):

first I lower the indices on : ##\frac{1}{3}\partial_c \eta^{wc} \eta^{zu}a_{wz}\partial_{\mu} \Phi ##


then, (this is the bit I'm more unsure of- get deltas from requiring the indices on the derivative and tensor to match...)when varying wrt ##\partial_{k}a^{mn}## :


##\frac{1}{3}\delta_{c,k}\delta_{m,w}\delta_{n,z}\eta^{wc}\eta^{zu}\partial_{\mu}\Phi ##


##=\frac{1}{3}\eta^{mk}\eta^{n\mu}\partial_{\mu}\Phi ##


so for ##\frac{\partial L}{\partial_k(\partial_{k}{a_{mn}})}## get:


##\partial_k\frac{1}{3}\eta^{mk}\eta^{n\mu}\partial_{\mu}\Phi ##
##= \frac{1}{3}\partial^m\partial^n\Phi ##

And so I have got the first term of [2] but not the second term. :(

Thanks.
 
Last edited:

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