Hi. I am trying to prove that (2sin^4x(2cos^2x+1))/3 = [sin^2(2x)/6-1/3][cos(2x)].(adsbygoogle = window.adsbygoogle || []).push({});

I tried fixing the right side, changing cos2x to 1 - 2sin^2x, and I went all the way to

(4sin^2x-4sin^4x-2-8sin^4x+8sin^6x+4sin^2x)/6.

I am clueless on how to continue the proof. Please help. Thanks.

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# Euler's formula proof help

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