- #1

- 91

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2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!

- Thread starter btbam91
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- #1

- 91

- 0

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!

- #2

- 107

- 0

2^(1-i) = exp(ln[2^(1-i)]), go from there.

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!

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