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Euler's formula.

  1. Sep 16, 2010 #1
    Hey guys, I'm having trouble on understanding how:

    2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

    Thanks in advance!
     
  2. jcsd
  3. Sep 16, 2010 #2
    2^(1-i) = exp(ln[2^(1-i)]), go from there.
     
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