Euler's formula.

  • Thread starter btbam91
  • Start date
  • #1
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Hey guys, I'm having trouble on understanding how:

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!
 

Answers and Replies

  • #2
107
0
Hey guys, I'm having trouble on understanding how:

2^(1-i) expands to 2cos(ln2)-2i(sin(ln2))

Thanks in advance!
2^(1-i) = exp(ln[2^(1-i)]), go from there.
 

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