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Euler's method approximation

  1. Feb 3, 2013 #1
    1. The problem statement, all variables and given/known data

    consider the function f(x) = aln(x+2). Given that f'(1) = a/3, what is the approximate value of f(0.98)?





    2. Relevant equations
    f(x1) = f(x0) + f'(x0)x(x1-x0)


    3. The attempt at a solution
    I solved it and get

    f(.98) = aln(1+2) + (.098-1) = aln(3) - (.02)(a/3) <= not an answer

    the bad thing is my teacher don't give me the increment interval. ..So I assumed it is .02
     
  2. jcsd
  3. Feb 3, 2013 #2

    Dick

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    That seems all right. Though you probably mean (0.98-1)(a/3) in you solution. Does 'not an answer' mean this is multiple choice? If so what are the possible answers?
     
  4. Feb 3, 2013 #3
    A. (0.98-1)(a/3) + aln(2.98)
    B. (a/3)aln(2.98) + .98
    C. -.02a/3
    D. (.98)ln(a/3)
    E. (a/3) (.98) + aln(2.98)

    none of them has aln3 like I solved
     
  5. Feb 3, 2013 #4

    Dick

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    I don't care much for any of those choices either.
     
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