Euler's polynomial proof

  1. without using a counter example, show a proof that Euler's polynomial equation P(n)=n^2+n+41 can not be used to generate all the primes.can a general proof be made to show that all primes cannot be generated by a specific polynomial?
  2. jcsd
  3. HallsofIvy

    HallsofIvy 41,260
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    Well, what, exactly, is "Euler's polynomial equation"? Don't you think that is important?
  4. thats the proposition made by Euler that P(n)=n^2+n+41 can generate all primes and it was suddenly proven false by using a counter example, isnt there any way he can be proven to be false?
  5. I believe you mean that P(n) would be prime for positive integers n, but there is now a general proof out there that no polynominal equation can generate only primes for all positive integers. I am sure that someone can cive you a link to a proof.
  6. See also Euler's formula for primes as posted in this thread was once widely thought to generate primes for any integer n, but as shown by this link that was false. The proof is simple an noted in the link. Assume that P(x) is a polynominal in x that gives a prime [tex]p[/tex] for the value [tex]n[/tex].
    But then [tex]p|P(n+kp)[/tex] for all integer [tex]k[/tex] so these numbers must be composite for every k so the polynominal is a constant, p, rather than a polynominal.

    P.S. Euler never said that the polynominal generated "all primes", but then that is obviously not what you meant is it?
  7. It is possible with polynomials in more variables, as the same wiki article points out:

  8. matt grime

    matt grime 9,395
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    That doesn't count - look at the restriction placed on both the input and output variables.
  9. but the same polynominal would generate composites also with large enough variables. Think how easy it would be to exceed the largest prime otherwise
  10. P(n) = n^2 + n + 41 =>
    P(40) = 40^2 + 40 + 41
    = 40 * 40 + 40 + 41
    = 40 * 41 + 41 = 41 * 41 = composite.
  11. CRGreathouse

    CRGreathouse 3,497
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  12. The positive values of the Jones polynomial for positive values of the variables are always primes and all primes can be obtained this way. The problem is just that the probability that a random choice of the input vaiables will yield a positive value is astronomically small. If finally, after billions of years of trying, some positive value is obtained, it will likely be a prime number like 23.
  13. CRGreathouse

    CRGreathouse 3,497
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    Was that in response to my post? I was incredulous about the claim that "once widely thought to generate primes for any integer n". It's obvious that no nonconstant polynomial can produce primes for all n, so it's hard for me to believe that this was ever believed. But it could be true, so I was looking for ramsey2879 or someone else to comment on that.
  14. I am 60 and some years old so I some times don't remember exactly what I read too well. The book is up in the attic. Some time I will look again at what was said about the polynominal. But that the polynominal does give composite values is of course easily shown.
  15. CRGreathouse

    CRGreathouse 3,497
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    If you do, I'd appreciate the effort if you post it.
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